6n^2-18n=24

answer and thorough explanation

n1=1, n2=4

Step-by-step explanation:

first divide both sides by 6 of the equation

=n^2-3n=4

n^2-3n-4=0 ... move the constant to the outerside

n^2-3n-4=0 ... write - 3 as a difference

n^2+n-4n-4=0

factor out n

n * (n+1) - (4n-4) = 0

nx (n+1) - 4 (n+1) = 0

(n+1) * (n-4) = 0

=n (+1=0) work out

n-4=0

n=-1

n-4=0

now solve for n

and the answer will be; n1=-1, n2=4