Solve the equation by factoring.

3z2 + 3z - 6 = 0

z = 3 or z = 2

3z^2 + 3z - 6 = 0

3

3 (z^2 + z - 2) = 0

3 (z+2) (z - 1) = 0

z + 2-2 = 0 - 2

z = - 2

z - 1 + 1 = 0 + 1

z = 1

Step-by-step explanation:

factor out the GCF (3) and divide everything by it, and then set it equal to zero. since you have a degree of 2, factor it into two binomials that start with the square root of the first term and end with the square root of the second term. 3=0 is extraneous solution so we leave it, then we set each binomial equal to zero to solve for z.

note: your solutions is based on the degree or the exponent of the polynomial or the function.