Write the equation in standard form for the circle x2+y2-2y-43=0.

Question

Mathematics

Karla Anderson

8 May, 10:31

Write the equation in standard form for the circle x2+y2-2y-43=0.

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Answers (2)

Know the Answer?

Asher Rice · Answer 1

x^2 + y (y - 2) = 43

Step-by-step explanation:

Step 1: Add 43 to both sides

x^2 + y^2 - 2y - 43 + 43 = 0 + 43

x^2 + y^2 - 2y = 43

Step 2: Pull out the y from y^2 - 2y

x^2 + y^2 - 2y = 43

x^2 + y (y - 2) = 43

Answer: x^2 + y (y - 2) = 43

Jadon Clark · Answer 2

The general equation of a circle is:

(x-a) ² + (y-b) ²=r², where a and b are the coordinates of the center, and r is the radius.

Now: x²+y²-2y-43=0

x²+y²-2y+1-44=0

Sqrt (44) = 6.63, so we get:

Answer: x² + (y-1) ²=6.63²