Jane, Kindra, and Joyce have old coin collections. Jane has 3 times as many coins as Joyce. Kindra has 2 more than twice the number Joyce has. Together they have 56 old coins. How many coins does each of them have?

Jane has 27 coins, Kindra has 20 coins and Joyce has 9 coins.

Step-by-step explanation:

Let Joyce's number of old coins be 1 unit / base unit.

Therefore, Jane has 3u coins and Kindra has 2u + 2 coins.

Total = 1u + 3u + 2u + 2 = 6u + 2

6u + 2 = 56

6u = 54

1u = 9

Joyce has 9 coins.

Jane = 3 x 9 = 27

Jane has 27 coins.

Kindra = 2 x 9 + 2 = 18 + 2 = 20

Kindra has 20 coins.