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12 February, 23:36

Laura will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $55.98 and costs an additional $0.13 per mile driven.

The second plan has an initial fee of $69.98 and costs an additional $0.08 per mile driven. How many miles would Laura need to drive for the two plans to cost

the same?

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  1. 13 February, 00:27
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    Answer: it would take 280 miles before Laura pays the same amount for both plans ...

    Step-by-step explanation:

    Let x represent the number of miles that Laura drives using either the first plan or the second plan

    Let y represent the total cost of x miles when using the first plan

    Let y represent the total cost of x miles when using the second plan

    The first plan has an initial fee of $55.98 and costs an additional $0.13 per mile driven. This means that the total cost of x miles would be

    y = 0.13x + 55.98

    The second plan has an initial fee of $69.98 and costs an additional $0.08 per mile driven. This means that the total cost of x miles would be

    z = 0.08x + 69.98

    To determine the number of miles that Laura would drive before the amount for both plans becomes the same, we would equate y to z. It becomes

    0.13x + 55.98 = 0.08x + 69.98

    0.13x - 0.08x = 69.98 - 55.98

    0.05x = 14

    x = 280
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