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9 May, 21:44

another rectangle has length and width in the ratio of 3:2. If the length is increased by eight and the width is increased by 50%, the ratio of the new perimeter to the original perimeter is 8:5. Find the area of the new rectangle

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  1. 10 May, 00:53
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    Area of the new rectangle = 148.8 cm square

    Step-by-step explanation:

    Let x be the dimensions of the rectangle then the

    Perimeter of the Original rectangle = 2 (L+B)

    = 2 (3x+2x) = 2 (5x) = 10xcm

    If the length is increased by eight the new length would be 3x + 8

    and width would be 2x+x = 3x after 50 % increase

    Perimeter of the new rectangle = 2 (L+B)

    = 2 (3x+8 + 3x)

    = 2 (6x+8)

    = 12x + 16

    Ratio of the new perimeter to the original perimeter is

    New perimeter : Original perimeter

    8 : 5

    12x + 16 : 10x cm

    80x = 60x + 16

    20x = 16

    x = 16/20 = 4/5

    Putting the value of length and breadth in place of x

    Area of the new rectangle = L*B = 3 * (4/5) + 8 * 3 (4/5) =

    = 12 + 40/5 * 12/5

    = 62/5 * 12/5

    = 744/5

    = 148.8 cm square
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