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23 July, 14:07

For the arithmetic series 1/3+4/3+7/3 + ... determine S7

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  1. 23 July, 16:30
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    S7 = 70/3

    Step-by-step explanation:

    Given:

    series: 1/3+4/3+7/3 + ...

    a = 1/3

    Find:

    S7

    Computation

    d = a2-a1

    d = 4/3 - 1/3

    d = 1

    ⇒ Sn = n/2[2a + (n-1) d]

    ⇒ S7 = 7/2[2 (1/3) + (7-1) 1]

    ⇒ S7 = 7/2[2/3+6]

    ⇒ S7 = 7/2[20/3]

    S7 = 70/3
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