A standard fair dice is rolled twice.

What is the probability of getting an odd number on the first roll and any factor of 12 on the other?

Step-by-step explanation:

It is too bad that the singular of the word dice is die.

Anyway, if your die is a 6-sided, unloaded cube with from 1 to 6 dots on a side, the numbers represented by the dots are 1, 2, 3, 4, 5, and 6.

The odd numbers are 1, 3, and 5. So three of the six numbers are odd. Rolling any one of these is a favorable outcome.

There are six outcomes in all.

P (rolling an odd number) = number of favorable outcomes : number of all outcomes

=36=12, or. 50 in decimal.