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31 March, 10:03

Use the given degree of confidence and Sample data to construct income confidence interval for the population proportion p. n=110, x=55; 88% confidence

A) 0.426 B) 0.442 C) 0.425 D) 0.421

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  1. 31 March, 10:19
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    (0.426, 0.574)

    Step-by-step explanation:

    Confidence interval = proportion ± margin of error

    CI = p ± ME

    The proportion is:

    p = x / n

    p = 55/110

    p = 0.5

    Margin of error = critical value * standard error

    ME = CV * SE

    n > 30, so we can approximate CV with a normal distribution. At P = 88%, CV = 1.55.

    SE = √ (pq / n)

    SE = √ (0.5 (1 - 0.5) / 110)

    SE = 0.048

    So the margin of error is:

    ME = 1.55 * 0.048

    ME = 0.074

    So the confidence interval is:

    CI = 0.5 ± 0.074

    CI = (0.426, 0.574)
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