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24 September, 00:52

For the function y = - 1+6 cos (2π/7 (x-5)), what is the maximum value

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  1. 24 September, 04:38
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    5

    Step-by-step explanation:

    I'm assuming you want to find the maximum value of y

    recall that for any cosine function y = A cos (g (x)), where g (x) is any arbitrary function, that A represents the amplitude of the cosine function.

    By definition, the amplitude is the maximum the value which the cosine term can take.

    hence for your expression:

    y = - 1 + 6 cos (2π/7 (x-5))

    max value of y = - 1 + (max value of cosine function)

    max value of y = - 1 + (amplitude of cosine function)

    max value of y = - 1 + 6 = 5
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