How many ways can 6 different prize be distributed equally among three superior students?

There are 90 ways to distribute the prizes

Step-by-step explanation:

* Lets explain how to solve the problem

- There are 6 different prize distributed equally among 3 super students

∵ There are 6 prize are to be equally distributed among 3 students

∴ Each student will get ⇒ 6 : 3 = 2

∴ Each student takes 2 prize

* Order doesn't matter here because the 3 students are super

so we can start with any one of them

# The 1st student will get 2 prize from 6

∴ The choices = 6C2

# The 2nd student will get 2 prize from remaining 4 prize

∴ The choices = 4C2

# The 3rd student will get 2 prize from remaining 2 prize

∴ The choices = 2C2

* To find the total choices multiply the three choices above

∴ The total choices = 6C2 * 4C2 * 2C2

∴ The total choices = 15 * 6 * 1 = 90 choices

* There are 90 ways to distribute the prizes