Factor 6x? + x - 12 by grouping.

C

6x² + x - 12 = (2x + 3) (3x - 4)

Step-by-step explanation:

Factor 6x² + x - 12 by grouping

we need to rewrite the middle term as a sum of two terms whose product is (6 * - 12) = - 72 and whose sum is 1

The middle term = x = 9x - 8x

6x² + x - 12

= 6x² + 9x - 8x - 12 Grouping the first two terms and the last two terms

= (6x² + 9x) + ( - 8x - 12)

From the first two terms take 3x as a common and from the two terms take (-4) as a common

= 3x (2x + 3) - 4 (2x + 3)

Take (2x + 3) as a common

= (2x + 3) (3x - 4)