Y=x^2-10x-2

Find the equation of the axis of symmetry

The axis of symmetry would be (5, - 27). To find the axis you can use two equations but for this question I used - b/2a. In the equation, the a is 1 and the b is - 10. So, you would substitute it in and get 10/2 which would give you x=5. Then, you would substitute it into the equation. Like this - > y = (5) ^2-10 (5) - 2. You would end up with y=25-50-2. This would give you a y of - 27 leaving you with the answer (5,-27).