Solve the system using elimination

2x+3y=14

x+5y=14

NVM my answer was wrong so i edited it

x = 4, y = 2

Step-by-step explanation by elimination:

Solve the following system:

{2 x + 3 y = 14 | (equation 1)

x + 5 y = 14 | (equation 2)

Subtract 1/2 * (equation 1) from equation 2:

{2 x + 3 y = 14 | (equation 1)

0 x + (7 y) / 2 = 7 | (equation 2)

Multiply equation 2 by 2/7:

{2 x + 3 y = 14 | (equation 1)

0 x+y = 2 | (equation 2)

Subtract 3 * (equation 2) from equation 1:

{2 x+0 y = 8 | (equation 1)

0 x+y = 2 | (equation 2)

Divide equation 1 by 2:

{x+0 y = 4 | (equation 1)

0 x+y = 2 | (equation 2)

Collect results:

Answer: {x = 4, y = 2