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10 September, 05:05

A right triangle has sides of length 3, 4, and.

Find if it is the hypotenuse.

Find if it is one of the legs.

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Answers (2)
  1. 10 September, 05:25
    0
    Solution:

    Let the third side be = x

    Case 1. Find it if it's the hypotenuse.

    Solution : Pythagoras Theorem = (H) ² = (P) ² + (B) ²

    = On substituting the values = (n) ² = 4²+3²

    = x²=16+9

    = x² = 25

    = x=√25

    = x = 5

    Case 2. Find it if it's one of the legs

    = If it is one of the legs, then the longest side of them will be the hypotenuse which is 4.

    Legs = 3, n

    Hypotenuse = 4

    Pythagoras Theorem = (P) ² + (B) ² = (H) ²

    = 3²+x²=4²

    = 9+x² = 16

    = x² = 16-9

    = x² = 7

    = x = √7

    = x = 2.64 (approx.)
  2. 10 September, 08:46
    0
    5/hypotenuse, the square root of 7 / leg

    Step-by-step explanation:

    3^2+4^2=25 or 5^2. you use a^2+b^2=c^2. it would be one of the hypotenuses. If the missing number is a leg, you would do 4^2=3^2+x^2. 16=9+x^2, 7=x^2, so you plug in the numbers differently.
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