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24 August, 13:03

A bag contains 4 blue and 6 green marbles. Two marbles are selected at random from the bag. If the first marble is NOT replaced before the second marble is drawn, what is the P (blue second | green first) ?

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  1. 24 August, 13:58
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    I think it's 4/10

    Step-by-step explanation:

    P (B|G) = p (BnG) / p (G) =

    P (4x6) / 6 4x6=24.

    24/6 = 4/10
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