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Mathematics
Ashly Hurst
1 December, 04:50
What are the roots of the equation x^2+6x-9=10?
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Trevor Joyce
1 December, 07:28
0
-3+2sqrt7
-3-2sqrt7
Step-by-step explanation:
x^2+6x-9=10
x^2+6x-9-10=0
x^2+6x-19=0
ax^2+bx+c=0
a=1 b=6 c=-19
As cannot be solved by completing square we will use quadratic equation
x = (-b+sqrt (b^2-4ac)) / 2a and x = (-b-sqrt (b^2-4ac)) / 2a
x = (-6+sqrt (6^2-4*-19)) / 2 and x = (-6-sqrt (6^2-4*-19)) / 2
x = (-6+sqrt (36+76)) / 2 and x = (-6-sqrt (36+76)) / 2
x = (-6+4sqrt7) / 2 and x = (-6-4sqrt7) / 2
x = (-3+2sqrt7) and x = (-3-2sqrt7)
x=2.29 and x = - 8.29
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