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12 August, 18:35

Answer the following questions. a. In the general education course requirement at a college, a student needs to choose one each from social sciences, humanities, natural sciences, and foreign languages. There are 5 social science courses, 4 humanity courses, 4 natural science courses, and 3 foreign language courses available for general education.

a. How many different ways can a student choose general education courses from these 4 areas?

b. Four people are chosen from a 25-member club for president, vice president, secretary, and treasurer. In how many different ways can this be done?

c. In how many different ways can 5 tosses of a coin yield 2 heads and 3 tails?

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  1. 12 August, 21:51
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    a) N = 240 ways

    b) N = 303,600 ways

    c) N = 10 ways

    Step-by-step explanation:

    a) Given

    General course consist of one course from each of 4 groups.

    Social Science = 5 options

    Humanities = 4 options

    Natural sciences = 4 options

    Foreign language = 3 options.

    Therefore the total number of possible ways of selecting one each from each of the 4 groups is:

    N = 5*4*4*3 = 240 ways

    b) if four people are chosen from 25 member for four different positions, that makes it a permutation problem because order of selection is important.

    N = nPr = n! / (n-r) !

    n = 25 and r = 4

    N = 25P4 = 25! / (25-4) ! = 25!/21!

    N = 303,600 ways

    c) The number of ways by which 5 tosses of coin can yield 2 heads and 3 tails.

    N = 5! / (5-5) ! (2!) (3!)

    N = 5*4/2

    N = 10 ways
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