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1 December, 22:49

Juan starts walking at 4 miles per hour. An hour and a half later, Cathy starts jogging along the same route at 7 miles per hour. How long will it take Cathy to catch up with Juan?

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Answers (2)
  1. 2 December, 01:59
    0
    The answer to your question is 2 hours

    Step-by-step explanation:

    Data

    Juan speed = 4 mi/h

    Cathy speed = 7 mi/h

    t = x

    Formula

    speed = distance/time

    Solve for distance

    distance = speed x time

    d = s x t

    Distance travelled by Juan

    d = 4t

    Distance travelled by Juan in 1.5 h

    d = 4 (1.5)

    d = 6 mi

    total distance d = 6 + 4t

    Distance travelled by Cathy

    d = vt

    d = 7t

    Equal both equations

    6 + 4t = 7t

    Solve for t

    6 = 7t - 4t

    6 = 3t

    6/3 = t

    2 = t

    Cathy wll catch up with Juan in 2 hours
  2. 2 December, 02:28
    0
    Answer: it take Cathy 3.75 to catch up with Juan

    Step-by-step explanation:

    Let t represent the time it will take for Cathy to catch up with Juan. At time t hours when Cathy will catch up Juan, they would have covered the same distance.

    Juan starts walking at 4 miles per hour.

    Distance = speed *, time

    This means that the distance that Juan covered in to hours would be

    4 * t = 4t

    An hour and a half later, Cathy starts jogging along the same route at 7 miles per hour. Total time spent by Cathy would be t - 1.5

    Distance covered by Cathy would be

    7 (t - 1.5) = 7t - 10.5

    Since the distance covered is the sane, the.

    4t = 7t - 10.5

    7t - 4t = 10.5

    3t = 10.5

    t = 10.5/3 = 3.5 hours
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