The area of a rectangle is 66 ft2, and the length of the rectangle is 1 ft more than twice the width. Find the dimensions of the rectangle.

This is probably way overcomplicated but i cant remember how to do it

w = n

l = 2n+1

w*l = 66

n (2n+1) = 66

2n^2 + n = 66

2n^2 + n - 66 = 0

using quadratic equation

n = 11/2

width = 11/2 = 5.5

length = 11 + 1 = 12