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10 January, 01:11

The area of a rectangle is 66 ft2, and the length of the rectangle is 1 ft more than twice the width. Find the dimensions of the rectangle.

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  1. 10 January, 01:47
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    This is probably way overcomplicated but i cant remember how to do it

    w = n

    l = 2n+1

    w*l = 66

    n (2n+1) = 66

    2n^2 + n = 66

    2n^2 + n - 66 = 0

    using quadratic equation

    n = 11/2

    width = 11/2 = 5.5

    length = 11 + 1 = 12
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