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27 January, 13:08

Evaluate the expression 2x^2-y^1+3x^0 for x = 3 and y=5

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Answers (1)
  1. 27 January, 15:41
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    13

    Step-by-step explanation:

    2 (3) ^2 - (5) ^1+3 (3) ^0

    (3) ^2=9, 5^1=5, 3 (3) = 9

    2 (9) - 5+9^0

    2 (9) = 18

    9^0=0

    18-5=13
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