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10 May, 16:08

write a polynomial function of least degree with integral coefficients the zeros of which include 4 and 4-i

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  1. 10 May, 19:34
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    x³ - 12x² + 49x - 68

    Step-by-step explanation:

    Complex roots (zeros) occur in conjugate pairs

    Thus 4 - i is a zero then 4 + i is a zero

    Given the zeros are x = 4, x = 4 ± i, then

    the factors are (x - 4), (x - (4 - i)) and (x - (4 + i))

    The polynomial is the product of the factors, so

    p (x) = (x - 4) (x - 4 + i) (x - 4 - i) ← expand the second pair of factors

    = (x - 4) ((x - 4) ² - i²) → note i² = - 1

    = (x - 4) (x² - 8x + 16 + 1)

    = (x - 4) (x² - 8x + 17) ← distribute

    = x³ - 8x² + 17x - 4x² + 32x - 68 ← collect like terms

    p (x) = x³ - 12x² + 49x - 68
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