But The aquarium charges $12 per ticket for adults and $5per ticket for children. A group of 90 children and adult chaperones visited the aquartum on a held trip. If the total cost of their tickets was $548, how mamy chaperones were there?

Question

Mathematics

Damon Cain

28 October, 01:08

But The aquarium charges $12 per ticket for adults and $5per ticket for children. A group of 90 children and adult chaperones visited the aquartum on a held trip. If the total cost of their tickets was $548, how mamy chaperones were there?

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Answers (1)

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There were 76 childrens and 14 adults.

Step-by-step explanation:

Since the group has a total of 90 children and adults, then the sum of the number of adults with the number of children must be equal to 90 as shown below:

children + adults = 90

Since the total cost for their tickets was 548 then the number of children multiplied by the price of their ticket summed by the number of adults multiplied by the price of their ticket must be equal to that. We have:

5*children + 12*adults = 548

With these two equations we have a system of equations shown below:

children + adults = 90

5*children + 12*adults = 548

In order to solve this we will multiply the first equation by - 5, and sum both equations we have:

-5*children - 5*adults = - 450

5*children + 12*adults = 548

7*adults = 98

adults = 98/7 = 14

children + 14 = 90

children = 90 - 14 = 76

There were 76 childrens and 14 adults.