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15 February, 14:15

Which is equivalent to (9 y squared minus 4 x) (9 y squared + 4 x), and what type of special product is it? 81 y Superscript 4 Baseline minus 16 x squared, a perfect square trinomial 81 y Superscript 4 Baseline minus 16 x squared, the difference of squares 81 y Superscript 4 Baseline minus 72 x y squared minus 16 x squared, a perfect square trinomial 81 y Superscript 4 Baseline minus 72 x y squared minus 16 x squared, the difference of squares

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  1. 15 February, 15:57
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    Option B 81 y Superscript 4 Baseline minus 16 x squared, the difference of squares is correct.

    Step-by-step explanation:

    We need to solve:

    (9y^2 - 4x) (9y^2+4x)

    Finding the product:

    9y^2 (9y^2+4x) - 4x (9y^2+4x)

    81y^4+36y^2x-36y^2x-16x^2

    81y^4 - 16x^2

    Type of Special product

    The product is differences of square because

    81y^4 = (9y^2) ^2

    and 16x^2 = (4x) ^2

    So, 81y^4 - 16x^2 = (9y^2) ^2 - (4x) ^2

    Hence Option B 81 y Superscript 4 Baseline minus 16 x squared, the difference of squares is correct.
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