Ask Question
14 June, 02:54

find three consecutive odd integers such that the product of the first and third is 71 more than 10 times the second

+2
Answers (1)
  1. 14 June, 06:27
    0
    13, 15, 17

    Step-by-step explanation:

    x (x + 4) = 10 (x + 2) + 71

    x2 + 4x = 10x + 20 + 71

    x2 - 6x - 91 = 0

    (x + 7) (x - 13) = 0

    x + 7 = 0

    x = - 7

    -7, - 5, - 3

    x - 13 = 0

    x = 13

    13, 15, 17
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “find three consecutive odd integers such that the product of the first and third is 71 more than 10 times the second ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers