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30 November, 11:59

one number is 6 times a first number. a third number is 100 more than the first number. if the sum of the three numbers is 316, find the numbers

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  1. 30 November, 13:03
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    27, 162, and 127

    Step-by-step explanation:

    take x plus 6 times the first number x and the third number is (x+100). put it together and you get x+6x + (x+100) = 316 combine like terms to get 8x (x+6x+x) + 100=316, subtract 100 to both sides. 8x=216 divide by 8 and you get x=27. that's the first number, multiply it by 6 to get 162 which is the second and the third is 27+100 which is 127
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