The height of a rock t seconds after it is dropped off a cliff is given by the equation h = - 16t^2 + 256. How many seconds after the rock is dropped will it hit the ground?

4 seconds

Step-by-step explanation:

To hit the ground, the height here would be zero

Hence We equate the h here to zero.

This means 0 = - 16t^2 + 256

16t^2 = 256

t^2 = 256/16

t*2 = 16

t = 4s

The rock will hit the ground after

Answer: it will take 4 seconds after the rock is dropped to hit the ground.

Step-by-step explanation:

The equation representing the height of the rock, h dropped off a cliff after it has fallen for t seconds is

h = - 16t^2 + 256

By the time the rock hits the ground, its height above the ground would be zero. Thus, h = 0. Therefore

0 = - 16t^2 + 256

16t^2 = 256

t^2 = 256/16 = 16

Taking square root of both sides of the equation, it becomes

t = √16 = 4