How do I do this problem show work

Which of the following equations has only one solution? A. x^2 + 4x + 4 = 0 B. x^2 + x = 0 C. x^2 - 1 = 0

Question

Mathematics

Guest

26 June, 19:08

How do I do this problem show work

Which of the following equations has only one solution? A. x^2 + 4x + 4 = 0 B. x^2 + x = 0 C. x^2 - 1 = 0

+1

Answers (1)

Know the Answer?

Alan Wilson · Answer 1

Answer

A. is the answer

Step-by-step explanation:

Determine the number of solutions using the discriminant D=b^2-4 ac

D=4^-4 x 1 x 4

simplify the expression

D = 4^2-4 x 1 x 4

which is

D=0

since D=0, the quadratic equation has 1 real solution

How do I do this problem show workWhich of the following equations has only one solution? A. x^2 + 4x + 4 = 0 B. x^2 + x = 0 C. x^2 - 1 = 0

How do I do this problem show work

Which of the following equations has only one solution? A. x^2 + 4x + 4 = 0 B. x^2 + x = 0 C. x^2 - 1 = 0