Ask Question
30 July, 09:31

Find the equation of the line through (8,-6) which is perpendicular to the line y=x3-7.

Give your answer in the form y=mx+b

+2
Answers (1)
  1. 30 July, 11:33
    0
    y = (-1/3) (x + 10)

    Step-by-step explanation:

    The slope of the new (perpendicular) line is the negative reciprocal of the slope of the given line, which appears to be 3. Thus, the perpendicular line has the slope - 1/3.

    Using the slope-intercept form y = mx + b, and substituting the givens, we obtain:

    y = mx + b = > - 6 = (-1/3) (8) + b, or

    -6 = - 8/3 + b. We must solve for the y-intercept, b:

    Multiplying all three terms by 3 removes the fraction:

    -18 = - 8 + 3b. Thus, - 10 = 3b, and so b must be - 10/3.

    The desired equation is

    y = (-1/3) x - 10/3, or

    y = (-1/3) (x + 10)
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Find the equation of the line through (8,-6) which is perpendicular to the line y=x3-7. Give your answer in the form y=mx+b ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers