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30 January, 14:11

Two planes, which are 3500 miles apart, fly toward each other. Their speeds differ by 75mph. If they pass each other in 4 hours, what is the speed of each?

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Answers (2)
  1. 30 January, 14:31
    0
    400, 475

    Step-by-step explanation:

    Speed of planes : x and x+75

    4x + 4 * (x+75) = 3500

    4x + 4x + 300 = 3500

    8x = 3200

    x = 400

    X+75 = 475
  2. 30 January, 15:48
    0
    Answer: the speed of the first plane is 400 miles per hour.

    the speed of the second plane is 475 miles per hour.

    Step-by-step explanation:

    Let x represent the speed of the first plane.

    Their speeds differ by 75mph. This means that the speed of the second plane would be x + 75

    Two planes, which are 3500 miles apart, fly toward each other. If they pass each other in 4 hours, It means that both planed traveled a total distance of 3500 miles in 4 hours.

    Distance = speed * time

    Distance travelled by the first plane after 4 hours would be

    4 * x = 4x

    Distance travelled by the second plane after 4 hours is

    4 (x + 75) = 4x + 300

    Since the total distance travelled by both planes after 4 hours is 3500 miles, then

    4x + 300 + 4x = 3500

    8x = 3500 - 300 = 3200

    x = 3200/8 = 400 miles per hour

    The speed of the second plane would be

    400 + 75 = 475 miles per hour.
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