A moneybag contains 10 nickles and quarters that total is $1.50. How many of each are there?

5 Quarters

5 Nickels

Step-by-step explanation:

Amount of nickels: n

Amount of quarters: q

n = 5 cents

q = 25 cents

n+q=10

5n + 25q = 150

n=10-q

Substitute.

5 (10-q) + 25q=150

50-5q+25q=150

50+20q=150

20q=100

q=5

5 Quarters

5 Nickels

The other question:

Dimes = D

Quarters = Q

d + q = 13

q = 13 - d

10d + 25 (13 - d) = 220

Solve this equation.

10d + 325 - 25d = 220

325 - 15d = 220

325 = 220 + 15d

105 = 15d

7 = d

7 dimes

6 quarters

Third question:

11 tickets total = $34

Number of children's tickets = c

Number of adult's tickets = a

c = $2

a = $4

c + a = 11

a = 11 - c

2c + 4 (11-c) = 34

2c + 44 - 4c = 34

44 - 2c = 34

44 = 34 + 2c

10 = 2c

5 = c

5 children's tickets

6 adult's tickets

10nickels and 4 quarters