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17 December, 17:53

Sofia and Tess will each randomly choose one of the 10 integers from 1 to 10. What is the probability that

neither integer chosen will be the square of the other

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  1. 17 December, 18:45
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    2^2=4

    3^2=9

    Only four posible numbers

    2/10 for each because the results come in pairs. Since they both have 10 possible numbers its a 2/20 chance of getting a pair. Chances for neither being are 9/10
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