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8 July, 21:26

Multiple binomials by polynomials problem (2+3w) (w^2+6w+9)

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  1. 9 July, 00:26
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    3w³ + 20w² + 39w + 18

    Step-by-step explanation:

    It is given that,

    (2 + 3w) (w² + 6w + 9)

    To find the multiplication

    (2 + 3w) (w² + 6w + 9) = 2 * w² + 2 * 6w + 2 * 9 + 3w * w² + 3w * 6w + 3w * 9

    = 2w² + 12w + 18 + 3w³ + 18w² + 27w

    = 3w³ + 20w² + 39w + 18

    Therefore the final value = 3w³ + 20w² + 39w + 18
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