Multiple binomials by polynomials problem (2+3w) (w^2+6w+9)

3w³ + 20w² + 39w + 18

Step-by-step explanation:

It is given that,

(2 + 3w) (w² + 6w + 9)

To find the multiplication

(2 + 3w) (w² + 6w + 9) = 2 * w² + 2 * 6w + 2 * 9 + 3w * w² + 3w * 6w + 3w * 9

= 2w² + 12w + 18 + 3w³ + 18w² + 27w

= 3w³ + 20w² + 39w + 18

Therefore the final value = 3w³ + 20w² + 39w + 18