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29 October, 20:48

Factor Completely.

12v3 - 32v2 + 6v - 16

A. 2 (2v2 - 1) (3v - 8)

B. 2 (2v2 + 1) (3v - 8)

C. (2v2 + 1) (3v - 8)

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Answers (1)
  1. 30 October, 00:21
    0
    The answer to your question is letter B

    Step-by-step explanation:

    Data

    12v³ - 32v² + 6v - 16

    - Factor the first 2 terms by common factor

    12v³ - 32v² = 4v² (3v - 8)

    - Factor the last two terms by common factor

    6v - 16 = 2 (3v - 8)

    - Write the previous results

    4v² (3v - 8) + 2 (3v - 8)

    - Factor again by common factor

    (3v - 8) (4v² + 2)

    - Factor by common term

    2 (3v - 8) (2v² + 1)
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