Solve the system

x+3y=1; - 5x+4y=-5

x=1

y=0

Step-by-step explanation:

x+3y = 1 equation 1

-5x+4y = - 5 equation 2

using equation 1 we have:

x+3y = 1

x = 1-3y equation 3

using equation 3 in equation 2 we have:

-5 (1-3y) + 4y = - 5

-5 + 15y + 4y = - 5

19y - 5 = - 5

19y = - 5 + 5

19y = 0

y=0

so we have:

x = 1-3y

x = 1 - 3 (0)

x=1