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25 September, 21:49

Use the 4 step process to find the f' (x) of the function f (x) = x^2-3/2

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  1. Yesterday, 00:10
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    see below

    Step-by-step explanation:

    Modified problem

    (x) ^2-3/x

    Step 1: Find f (x+h)

    (x+h) ^2-3 / (x+h)

    x^2 + 2hx + h^2 - 3 / (x+h)

    Step 2: Find f (x + h) - f (x)

    x^2 + 2hx + h^2 - 3 / (x+h) - (x^2-3/x)

    Distribute the minus sign

    x^2 + 2hx + h^2 - 3 / (x+h) - x^2+3/x

    Combine like terms and get a common denominator

    2hx + h^2 - 3x / (x (x+h)) + 3 (x+h) / (x (x+h)

    2hx + h^2 + 3h / (x (x+h))

    Step 3: Find (f (x + h) - f (x)) / h

    (2hx + h^2+3h / (x (x+h))) / h

    2hx/h + h^2/h+3h / (x (x+h)) / h

    2x + h + 3 / (x (x+h))

    Step 4: Find lim h→0 (f (x + h) - f (x)) / h

    2x+0 + 3 / (x (x+0))

    2x + 3/x^2
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