Ask Question
24 June, 20:32

The height h (in feet) of a certain rocket t seconds after it leaves the ground is modeled by LaTeX: h/left (t/right) / : =/:-16t^2+64t+12. h (t) = - 16 t 2 + 64 t + 12. How long does it take the rocket to reach the maximum height?

+1
Answers (1)
  1. 25 June, 00:29
    0
    76 feet

    Step-by-step explanation:

    h = - 16t^2 + 64t + 12

    The maximum height will be reached after - b/2a secs

    a = - 16, b = 64, c = 12

    -b/2a = - 64/2 (-16)

    = - 64/-32

    = 2 secs

    The maximum height = - 16 (2) ^2 + 64 (2) + 12

    = - 16 (4) + 128 + 12

    = - 64 + 128 + 12

    = 76 ft
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The height h (in feet) of a certain rocket t seconds after it leaves the ground is modeled by LaTeX: h/left (t/right) / : =/:-16t^2+64t+12. ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers