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2 February, 19:52

Enter all answers to the nearest tenth.

A day care program has an average daily expense of $75.00. The standard deviation is $5.00. The owner takes a sample of 64 bills. What is the probability the mean of his sample will be between $70.00 and $80.00?

Step 1. Calculate a z-score for $70.00 -

Step 2. Give the probability for step 1. %

Step 3. Calculate the z-score for $80.00 +

Step 4. Give the probability for step 3. %

Step 5. Add the probabilities from steps 2&4. %

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Answers (1)
  1. 2 February, 23:45
    0
    What is the probability the mean of his sample will be between $70.00 and $80.00? = 64/64 = 1

    s1) = 99% = z score = 127/128

    s2) 64/64 = 1

    s3) 95% of 64 = 123/128

    s4) p) step 3 = 95% of 64 = 60.08 / 64 = 60/64 = 93.75%

    s5) P) of 2+4 = 283/292 = 96.92%
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