Use technology or a z-score table to answer the question.

The scores for a golf tournament are normally distributed with a mean of 210 and a standard

deviation of 80. Ella scored 230 at the tournament

What percent of golfers scored less than Ella?

Round your answer to the nearest whole number

A:60%

B:75%

C:77%

D:80%

Answer: A:60%

Step-by-step explanation:

Since the scores for a golf tournament are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ) / σ

Where

x = scores for the tournament.

µ = mean score

σ = standard deviation

From the information given,

µ = 210

σ = 80

We want to find the probability percent of golfers that scored less than Ella. It is expressed as

P (x < 230)

z = (230 - 210) / 80 = 0.25

Looking at the normal distribution table, the probability corresponding to the z score is 0.5987

Therefore, the percent of golfers that scored less than Ella is

0.5987 * 100 = 59.87

Approximately 60%