If f (3) = - 4, f' (3) = 4, g (3) = 2, and g' (3) = 0, find (f + g) ' (3).

(f + g) ' (3) = 4

Step-by-step explanation:

If f (3) = - 4, f' (3) = 4, g (3) = 2, and g' (3) = 0, find (f + g) ' (3).

We should know that:

[f (x) + g (x) ]' = f' (x) + g' (x)

So,

(f + g) ' (3) = f' (3) + g' (3)

By substitution with f' (3) = 4 and g' (3) = 0

So,

(f + g) ' (3) = f' (3) + g' (3)

= 4 + 0

∴ (f + g) ' (3) = 4