Solve the equation 2cos^2x + 3sinx = 3

x = 2 π n_1 + π/2 for n_1 element Z

or x = 2 π n_2 + (5 π) / 6 for n_2 element Z or x = 2 π n_3 + π/6 for n_3 element Z

Step-by-step explanation:

Solve for x:

2 cos^2 (x) + 3 sin (x) = 3

Write 2 cos^2 (x) + 3 sin (x) = 3 in terms of sin (x) using the identity cos^2 (x) = 1 - sin^2 (x):

-1 + 3 sin (x) - 2 sin^2 (x) = 0

The left hand side factors into a product with three terms:

- (sin (x) - 1) (2 sin (x) - 1) = 0

Multiply both sides by - 1:

(sin (x) - 1) (2 sin (x) - 1) = 0

Split into two equations:

sin (x) - 1 = 0 or 2 sin (x) - 1 = 0

Add 1 to both sides:

sin (x) = 1 or 2 sin (x) - 1 = 0

Take the inverse sine of both sides:

x = 2 π n_1 + π/2 for n_1 element Z

or 2 sin (x) - 1 = 0

Add 1 to both sides:

x = 2 π n_1 + π/2 for n_1 element Z

or 2 sin (x) = 1

Divide both sides by 2:

x = 2 π n_1 + π/2 for n_1 element Z

or sin (x) = 1/2

Take the inverse sine of both sides:

Answer: x = 2 π n_1 + π/2 for n_1 element Z

or x = 2 π n_2 + (5 π) / 6 for n_2 element Z or x = 2 π n_3 + π/6 for n_3 element Z