When a number is increased by 28%, the result is 47. What is the original number to the nearest tenth?

The original number was 36.7.

Step-by-step explanation:

Multipliers:

The multiplier for a increase of a% is 1 + a/100.

The multiplier for a decrease of b% is 1 - b/100.

In this question:

The original value is x.

Increased by 28%, so we have that 1 + (28/100) = 1.28x. Equals 47. We have to find x.

1.28x = 47

x = 47/1.28

x = 36.7

The original number was 36.7.