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26 February, 01:05

Find all solutions in the interval [0, 2π).

4 sin2x - 4 sin x + 1 = 0

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Answers (1)
  1. 26 February, 03:51
    0
    x = π/6, 5π/6

    Step-by-step explanation:

    4 sin² x - 4 sin x + 1 = 0

    (2 sin x - 1) ² = 0

    sin x = ½

    x = π/6, 5π/6
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