I roll a six-sided die 4 times. Find chances for each of the following events: a) the first die roll is bigger than the second or the first roll is a

=0.5278

Step-by-step explanation:

a) The first die roll is bigger than the second or the first roll is a 3

Cases for 2 rolls are (1,1) (1,2) (1,3) ... (1,6), (2,1) (2,2) ... (total 36)

We will get 6 cases when they are equal and 15 when 1st is bigger and 15 when 1st is smaller

So Let A is the event when first roll bigger

B is the event when First roll=3

So

P (A) = 15/36

P (B) = 1/6

P (A and B) = 2/36

So

P (A or B) = P (A) + P (B) - P (A and B)

=15/36+1/6-2/36

=19/36

=0.5278