Simultaneous equations:

Find two numbers whose difference is 5 and whose sum is 11.

x=8; y=3

Step-by-step explanation:

suppose,

one of the number is x

other one is y; x>y

according to the question,

x-y = 5 ... (1)

x+y=11 ... (2)

(2) + (1) = >

x+y+x-y=11+5

2x=16

x=8 [divided by 2 on both side]

then,

(2) - (1) = >

x+y-x+y=11-5

2y=6

y=3 [divided by 2 on both side]

8 and 3

Step-by-step explanation:

Let x and y be the 2 numbers with x > y, then

x - y = 5 → (1)

x + y = 11 → (2)

Add the 2 equations together term by term to eliminate y

2x = 16 (divide both sides by 2)

x = 8

Substitute x = 8 into (2)

8 + y = 11 (subtract 8 from both sides)

y = 3

The 2 numbers are 8 and 3