A rectangular house has a perimeter of 40 metres and the length is 4 metres more than the width. What are the dimensions of the house?

8m, 12m, area of the house is 32m²

Step-by-step explanation:

P=2l+2w

We are given,

P=40cm

l=w+4

Plug these into the first formula and solve for the dimensions,

length and width, of the rectangle:

40=2 (w+4) + 2w Simplify

40=2w+8+2w

40=4w+8

32=4w

8=w OR the width is 8m,

therefore,

the length is

l=w+4

l=8+4 m

l=12m

area of the house is = (8. 4) m² = 32m²

let breadth be 'b' and then, length would be '4+b'

Step-by-step explanation:

perimeter = 2[l+b]

a/q

40 = 2[4+b+b]

40 = 2[4+2b]

20=4+2b

2b=20-4

2b=16

b=8

.:l=4+b=4+8=12

.: dimensions of house are: 12*8