Ask Question
24 May, 01:17

Bob's age is 4 times greater than Suzan's age. Dakota is three years younger than Suzan. The sum of Bob's, Suzan's, and Dakota's age is 93. What is Suzan's age

+1
Answers (2)
  1. 24 May, 01:35
    0
    Answer: Susan is 16 years old.

    Step-by-step explanation:

    Let x represent Susan's age.

    Bob's age is 4 times greater than Suzan's age. This means that Bob's age is 4x.

    Dakota is three years younger than Suzan. This means that Dakota's age is x - 3

    The sum of Bob's, Suzan's, and Dakota's age is 93. This means that

    4x + x - 3 + x = 93

    4x + x + x = 93 + 3

    6x = 96

    x = 96/6 = 16

    Bob's age = 4x = 4 * 16 = 64

    Dakota's age = x - 3 = 16 - 3 = 13
  2. 24 May, 04:23
    0
    Suzan is 16

    Step-by-step explanation:

    16 (suzan)

    6x4=64 (bob)

    16-3=13 (dakota

    16+64+13=93
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Bob's age is 4 times greater than Suzan's age. Dakota is three years younger than Suzan. The sum of Bob's, Suzan's, and Dakota's age is 93. ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers