The Sun hits a 30 foot flagpole at a 60° angle and casts an unobstructed 52 foot shadow. If a building is built 32 feet away, what height will the shadow strike the side of the building? (round to nearest tenth)

A) 11.0 ft

B) 11.5 ft

C) 12.2 ft

D) 12.5 ft

Question

Mathematics

Guest

22 December, 21:32

The Sun hits a 30 foot flagpole at a 60° angle and casts an unobstructed 52 foot shadow. If a building is built 32 feet away, what height will the shadow strike the side of the building? (round to nearest tenth)

A) 11.0 ft

B) 11.5 ft

C) 12.2 ft

D) 12.5 ft

+5

Answers (1)

Know the Answer?

Cecilia Cisneros · Answer 1

Answer: 11.5 ft

Step-by-step explanation:

The length of the shadow of the building = length of the shadow - distance of the building

= 52 - 32

= 20

Let the height the shadow strike the side of the building be h

then by similar shape rule

h / 20 = 30 / 52

52h = 30 x 20

52h = 600

h = 600/52

h = 11.53846154

h ≈ 11.5

The Sun hits a 30 foot flagpole at a 60° angle and casts an unobstructed 52 foot shadow. If a building is built 32 feet away, what height will the shadow strike the side of the building? (round to nearest tenth)A) 11.0 ftB) 11.5 ftC) 12.2 ftD) 12.5 ft

The Sun hits a 30 foot flagpole at a 60° angle and casts an unobstructed 52 foot shadow. If a building is built 32 feet away, what height will the shadow strike the side of the building? (round to nearest tenth)

A) 11.0 ft

B) 11.5 ft

C) 12.2 ft

D) 12.5 ft