Ask Question
21 May, 10:27

3. Joe the barber charges $32 for a shave and haircut and $20 for just a haircut. Based on experience, he determines that the probability that a randomly selected customer comes in for a shave and"

haircut is 0.85, the rest of his customers come in for just a haircut. Let J = what Joe charges a

randomly selected customer.

(a) Give the probability distribution for J.

(b) find and interpret the mean of J, Mj

(c) find and interpret the standard deviation of J, standard deviation J

+1
Answers (1)
  1. 21 May, 13:49
    0
    A. Give the probability distribution for J.

    J 20 32

    p 0.15 0.85

    B. Find and interpret the mean of J, Mj

    Mj = 30.2

    This means that the average customer that come in spends $ 30.20 at the barber shop

    C. Find and interpret the standard deviation of J, standard deviation J

    sdJ = 4.28

    This means that the average customer that come in could spend + / - $ 4.28 at the barber shop, from $ 25.92 to $ 34.48

    Step-by-step explanation:

    Let's write our table of probabilities for the services provided by Joe the barber, this way:

    A. Give the probability distribution for J.

    J 20 32

    p 0.15 0.85

    B. Find and interpret the mean of J, Mj

    Mj = (20 * 0.15) + (32 * 0.85)

    Mj = 3 + 27.2 = 30.2

    This means that the average customer that come in spends $ 30.20 at the barber shop

    C. Find and interpret the standard deviation of J, standard deviation J

    sdJ = √ (20 - 30.2) ² * 0.15 + (32 - 30.2) ² * 0.85

    sdJ = √15.606 + 2.754

    sdJ = 4.28

    This means that the average customer that come in could spend + / - $ 4.28 at the barber shop, from $ 25.92 to $ 34.48
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “3. Joe the barber charges $32 for a shave and haircut and $20 for just a haircut. Based on experience, he determines that the probability ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers