In order to solve the system of equations below, Harvey multiplies each equation by a constant to eliminate the x terms.
7 x + 3 y = 5. 2 x + 5 y = negative 11.
What are the resulting equations?
14 x + 6 y = 10. Negative 14 x minus 35 y = 77.
14 x + 6 y = 10. Negative 14 x + 35 y = 77.
14 x + 6 y = 10. Negative 14 x minus 35 y = negative 77.
Negative 14 x minus 6 y = 10. 14 x + 35 y = negative 77.
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Home » Mathematics » In order to solve the system of equations below, Harvey multiplies each equation by a constant to eliminate the x terms. 7 x + 3 y = 5. 2 x + 5 y = negative 11. What are the resulting equations? 14 x + 6 y = 10. Negative 14 x minus 35 y = 77.